How would South bid with the hand below if North opened 2NT (20 - 22) and
had one of the 2 possible hands below?
North hand A
North hand B
If no transfers are being used the NS bidding in case A might be 2NT – 3S
- 4S – 4NT – 5H – 6S – Pass.
In case B it might be 2NT – 3S - 3NT – 4NT (quantitative) – 6NT –
But how would the bidding go if transfers were being used? If the bidding
began 2NT – 3H – 3S – 3NT then in case A North would respond 4S and 6S would be
reached. But if North had hand B then he would pass 3NT and so NS would fail to
reach the 6NT slam.
Is there a transfer bidding approach that would reach a slam whichever hand